Electric Field Between Capacitor Plates#
Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electrical field is \(E = {{params.a }} \times 10^5 \textrm{ V/m}\). When the space is filled with dielectric, the electrical field is \(E = {{params.b }} \times 10^5 \textrm{ V/m}\).
Part 1#
What is the surface charge density on each surface of the dielectric?
Answer Section#
Please enter a numeric value.
Part 2#
What is the dielectric constant?
Answer Section#
Please enter a numeric value.
Attribution#
Problem is from the OpenStax University Physics Volume 2 textbook, licensed under the CC-BY 4.0 license.