Electric Field Between Capacitor Plates#

Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electrical field is \(E = {{params.a }} \times 10^5 \textrm{ V/m}\). When the space is filled with dielectric, the electrical field is \(E = {{params.b }} \times 10^5 \textrm{ V/m}\).

Part 1#

What is the surface charge density on each surface of the dielectric?

Answer Section#

Please enter a numeric value.

Part 2#

What is the dielectric constant?

Answer Section#

Please enter a numeric value.

pl-submission-panel#

pl-answer-panel#

Attribution#

Problem is from the OpenStax University Physics Volume 2 textbook, licensed under the CC-BY 4.0 license.
Image representing the Creative Commons 4.0 BY license.