Velocity From Graph#

Refer to the following figure.

A graph of position vs time. At 0 seconds, the position is at 1m. At 1 second, the position is at 2m. There is a constant increase of 1m per second from 0 seconds to 1 second. At 1 to 2 seconds, there is no change in m and the position remains at 2m. At 3 seconds, the position is at 0m. From 2 to 3 seconds, there is a constant decrease of 2 m per second.

Figure: Position vs. time graph for the following two questions.

Part 1#

At \(t=\) 0.5\(s\), what is the x-component of the instantaneous velocity of the object whose position vs. time graph is shown in the figure?

Answer Section#

  • 1 \(m/s\)

  • -0.5 \(m/s\)

  • -2 \(m/s\)

  • 2 \(m/s\)

  • -1 \(m/s\)

Part 2#

For the object whose position vs time graph is shown in the figure above, the x-component of the average velocity (\(v\_{avg,x ; 0 \rightarrow 3}\)) and average speed (\(v\_{avg ; 0 \rightarrow 3}\)) over the time interval t=0s to t=3s are:

Answer Section#

  • \(v_{avg,x \; 0 \rightarrow 3}\) = -0.33 \(m/s\) and \(v_{avg \; 0 \rightarrow 3}\)= 1 \(m/s\)

  • \(v_{avg,x \; 0 \rightarrow 3}\) = -0.33 \(m/s\) and \(v_{avg \; 0 \rightarrow 3}\)= 0.33 \(m/s\)

  • \(v_{avg,x \; 0 \rightarrow 3}\) = -0.35 \(m/s\) and \(v_{avg \; 0 \rightarrow 3}\)= 0.5 \(m/s\)

  • \(v_{avg,x \; 0 \rightarrow 3}\) = -0.5 \(m/s\) and \(v_{avg \; 0 \rightarrow 3}\)= -2 \(m/s\)

  • \(v_{avg,x \; 0 \rightarrow 3}\) = -2 \(m/s\) and \(v_{avg \; 0 \rightarrow 3}\)= -0.5 \(m/s\)

Attribution#

Problem is licensed under the CC-BY-NC-SA 4.0 license.
The Creative Commons 4.0 license requiring attribution-BY, non-commercial-NC, and share-alike-SA license.