Force and Momentum#
The momentum of an object as a function of time is given by \(\vec{p} = (\)-4t^3 + 5t^2 + 9t\()\hat{\imath} + (\)3t^3 - t^2 + 6t\()\hat{\jmath}\) where \(p\) is in \(kg\cdot m/s\) and \(t\) is in seconds.
Part 1#
What is the net force on the object at \(t=\) 15.9 \(s\)?
Answer Section#
0 N
(-2870.0\(\hat\imath\) + 2250.0\(\hat\jmath\)) N
(2870.0\(\hat\imath\) - 2250.0\(\hat\jmath\)) N
(-2870.0\(\hat\imath\) - 2250.0\(\hat\jmath\)) N
(2870.0\(\hat\imath\) + 2250.0\(\hat\jmath\)) N
(5740.0\(\hat\imath\) + 2250.0\(\hat\jmath\)) N
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.