Force and Momentum#
The momentum of an object as a function of time is given by \(\vec{p} = (\)t^3 + 5t^2 - 6t\()\hat{\imath} + (\)2t^2 - 5t\()\hat{\jmath}\) where \(p\) is in \(kg\cdot m/s\) and \(t\) is in seconds.
Part 1#
What is the net force on the object at \(t=\) 9.18 \(s\)?
Answer Section#
0 N
(339.0\(\hat\imath\) + 31.7\(\hat\jmath\)) N
(-339.0\(\hat\imath\) - 31.7\(\hat\jmath\)) N
(339.0\(\hat\imath\) - 31.7\(\hat\jmath\)) N
(-339.0\(\hat\imath\) + 31.7\(\hat\jmath\)) N
(-678.0\(\hat\imath\) + 31.7\(\hat\jmath\)) N
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.