The Magnitude of a Particle’s Vector#

Question Text#

A particle has a trajectory given as \(\vec{r} = (\) \(-9t^2 + 5t\) \() \hat{\imath} + (\) \(-9t^2 + 3t\) \() \hat{\jmath}\) \(m\) for \(t\) given in seconds. What is the magnitude of the acceleration vector for this particle at \(t = \) \(17\) \(s\)?

Answer Section#

Please enter in a numeric value in \(m/s\).


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