Truck Up Hill#

A truck accelerates up a 10 \(^\circ\) incline. For a box in the back of the truck as shown in Fig. (i), the free body diagram is shown in Fig. (ii). The coefficient of friction between the box and the truck is \(\mu_s\) . At the point of slipping, the acceleration of the truck is:

../../../../../_images/truckuphill1.png

Part 1#

Answer Section#

  • a= \(\mu_s g - g\sin\)(10\(^\circ\))

  • a < \(\mu_s g\cos\)(10\(^\circ\)) - \(g\sin\)(10\(^\circ\))

  • a=\(\mu_s g\cos\)(10\(^\circ\)) - \(g\sin\)(10\(^\circ\))

  • a=\(\mu_s g\sin\)(10\(^\circ\))- \(g\cos\)(10\(^\circ\))

  • This cannot be found from the information given.

Attribution#

Problem is licensed under the CC-BY-NC-SA 4.0 license.
The Creative Commons 4.0 license requiring attribution-BY, non-commercial-NC, and share-alike-SA license.