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Part 1#

The change in momentum of a falling mass attached to a fixed rope is equal to:

Answer Section#

  • \(mg(t_2-t_1)\)

  • \(mv^2/2\)

  • integral of the net force over the stretching time of the rope

  • mass multiplied by the average velocity

  • \(mg(L_2-L_1)\)

Attribution#

Problem is licensed under the CC-BY-NC-SA 4.0 license.
The Creative Commons 4.0 license requiring attribution-BY, non-commercial-NC, and share-alike-SA license.

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