Aplha Particle in Magnetic Field#
An alpha-particle (\(m = 6.64 \times 10^{-27} \textrm{ kg}, q = 3.2 \times 10^{-19} \textrm{ C}\)) travels in a circular path of radius \({{params.r}} \textrm{ cm}\) in a uniform magnetic field of magnitude \({{params.B}} \textrm{ T}\).
Part 1#
What is the speed of the aplha-particle?
Answer Section#
Please enter a numeric value.
Part 2#
What is the kinetic energy of the alpha-particle in electron-volts?
Answer Section#
Please enter a numeric value.
Part 3#
Through what potential difference must the particle be accelerated in order to give it this kinetic energy?
Answer Section#
Please enter a numeric value.
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.