# Aplha Particle in Magnetic Field#

An alpha-particle ($$m = 6.64 \times 10^{-27} \textrm{ kg}, q = 3.2 \times 10^{-19} \textrm{ C}$$) travels in a circular path of radius $${{params.r}} \textrm{ cm}$$ in a uniform magnetic field of magnitude $${{params.B}} \textrm{ T}$$.

## Part 1#

What is the speed of the aplha-particle?

## Part 2#

What is the kinetic energy of the alpha-particle in electron-volts?

## Part 3#

Through what potential difference must the particle be accelerated in order to give it this kinetic energy?