Cosmic Ray Electron#

Question Text#

A cosmic-ray electron moves at 3.9$\times {10}^6\text{ m/s}$ perpendicular to Earth’s magnetic field at an altitude where the field strength is 3.3$\times {10}^{-5}\text{ T}$. What is the radius of the circular path the electron follows?

Answer Section#

Attribution#

Problem is from the OpenStax University Physics Volume 2 textbook, licensed under the CC-BY 4.0 license.