Cosmic Ray Electron#

Question Text#

A cosmic-ray electron moves at 6.0\(\times 10^6 \textrm{ m/s}\) perpendicular to Earth’s magnetic field at an altitude where the field strength is 8.0\( \times 10^{-5} \textrm{ T}\). What is the radius of the circular path the electron follows?

Answer Section#

pl-submission-panel#

Attribution#

Problem is from the OpenStax University Physics Volume 2 textbook, licensed under the CC-BY 4.0 license.
Image representing the Creative Commons 4.0 BY license.