Pendulum Gravity#
Part 1#
A pendulum with a period of 1.95 \(\rm{s}\) in one location (g = 9.807 \(\rm{m/s^2}\)) is moved to a new location where the period is now 1.8359999999999999 \(\rm{s}\). What is the acceleration due to gravity at its new location?
Answer Section#
Please enter a numeric value in \(\rm{m/s^2}\).
Attribution#
Problem is from the OpenStax University Physics Volume 1 textbook, licensed under the CC-BY 4.0 license.