Work Done By Force#
Between time \(t =\) 5 \(s\) and \(t =\) 9 \(s\), a force \(\vec{F}\) = ( 1.8 \(\hat\imath\) - 5.9 \(\hat\jmath\) ) N moves a 6.7 kg object along a trajectory \(\Delta\vec{r}\) = ( 2.7 \(\hat\imath\) - 1.9 \(\hat\jmath\) ) m.
Part 1#
How much work is done by this force?
Answer Section#
-6.4 \(J\)
16.0 \(J\)
110.0 \(J\)
2.4 \(J\)
-16.0 \(J\)
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.