Position XY 4a#
Part 1#
A particle’s path follows the trajectory shown in the figure. Which of the following statements is correct?

Answer Section#
For \(x>0\), the particle’s instantaneous acceleration is non-zero.
For \(x>0\), the particle’s instantaneous velocity is constant.
For \(x>0\), the particle’s instantaneous velocity is in the \(\hat{\imath}\) and \(\hat{\jmath}\) directions.
For \(x>0\), the particle’s instantaneous acceleration is in the \(-\hat{\imath}\) and \(\hat{\jmath}\) directions.
No information about the particle’s velocity or acceleration can be found from its trajectory.
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.