Shooting a Steel Ball#

A small steel ball is shot at 4 $$m/s$$ at a 71$$^{\circ}$$ angle above the horizontal direction and its motion is well approximated by projectile motion.

Part 1#

When the ball returns to its original height, its velocity $$\overrightarrow{v} = (v_x, v_y)$$ is:

• $$(4\cos(71^{\circ}), \; -4\sin(71^{\circ}))$$

• $$(4\cos(71^{\circ}), \;4\sin(71^{\circ}))$$

• $$(4\sin(71^{\circ}), \; -4\cos(71^{\circ}))$$

• $$(4\sin(71^{\circ}), \;4\cos(71^{\circ}))$$

• $$(-4\cos(71^{\circ}), \; -4\sin(71^{\circ}))$$

• $$(-4\sin(71^{\circ}), \;4\cos(71^{\circ}))$$