Position XY 3a#
Part 1#
A particle follows the trajectory shown in the figure without stopping along it’s path. What can you conclude aboout the particle’s motion?
![An image showing a particle's trajectory on a cartesian plane (x versus y). For negative x-coordinates, the particle follows a concave down trajectory with positive y-coordinates. At the y-axis, the particles trajectory is parallel to the x-axis. For positive x-coordinates, the particle follows a concave up trajectory with positive y-coordinates.](../../../../../_images/PositionXYa2.png)
Answer Section#
At \(x = 0\), the particle is moving in the \(\hat{\imath}\) direction.
At \(x = 0\), the particle is moving in the \(-\hat{\imath}\) direction.
At \(x = 0\). the particle is moving in the \(\hat{\jmath}\) direction.
At \(x = 0\), the particle is moving in the \(-\hat{\jmath}\) direction.
No information about the particle’s direction can be found from its trajectory.
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.