Gravity Vs Electric Forces

Gravity Vs Electric Forces#

The gravitational force \(F_G\) has the same form as Coulomb’s law for the electric force \(F_E\) , but it is always an attractive force.

Useful Info#

The gravitational force between two objects with masses \(m_1\) and \(m_2\) separated by a distance \(r\) is given by \(F_G = \frac{Gm_1m_2}{r^2}\), where \(G = 6.67 \times 10^{-11}\) \(\rm{\frac{Nm^2}{kg^2}}\). The electric force between two objects with charges \(q_1\) and \(q_2\) separated by a distance \(r\) is given by \(F_E = \frac{kq_1q_2}{r^2}\), where \(k = 8.99 \times 10^9\) \(\rm{\frac{Nm^2}{C^2}}\).

Part 1#

Find the ratio of the electric force to the gravitational force between a proton (\(m_p = 1.67 \times 10^{-27}\) \(\rm{kg}\), \(q_p = 1.602 \times 10^{-19}\) \(\rm{C}\)) and an electron (\(m_e = 9.11 \times 10^{-31}\) \(\rm{kg}\), \(q_e = -1.602 \times 10^{-19}\) \(\rm{C}\)).

Answer Section#

  • \(2.3 \times 10^{39}\)

  • \(1.7 \times 10^{19}\)

  • \(0.13\)

Attribution#

Problem is licensed under the CC-BY-NC-SA 4.0 license.
The Creative Commons 4.0 license requiring attribution-BY, non-commercial-NC, and share-alike-SA license.

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