Gravity Vs Electric Forces#
The gravitational force \(F_G\) has the same form as Coulomb’s law for the electric force \(F_E\) , but it is always an attractive force.
Useful Info#
The gravitational force between two objects with masses \(m_1\) and \(m_2\) separated by a distance \(r\) is given by \(F_G = \frac{Gm_1m_2}{r^2}\), where \(G = 6.67 \times 10^{-11}\) \(\rm{\frac{Nm^2}{kg^2}}\). The electric force between two objects with charges \(q_1\) and \(q_2\) separated by a distance \(r\) is given by \(F_E = \frac{kq_1q_2}{r^2}\), where \(k = 8.99 \times 10^9\) \(\rm{\frac{Nm^2}{C^2}}\).
Part 1#
Find the ratio of the electric force to the gravitational force between a proton (\(m_p = 1.67 \times 10^{-27}\) \(\rm{kg}\), \(q_p = 1.602 \times 10^{-19}\) \(\rm{C}\)) and an electron (\(m_e = 9.11 \times 10^{-31}\) \(\rm{kg}\), \(q_e = -1.602 \times 10^{-19}\) \(\rm{C}\)).
Answer Section#
\(2.3 \times 10^{39}\)
\(1.7 \times 10^{19}\)
\(0.13\)
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.
