Velocity and Acceleration of an Object#

If the velocity of an object in one-dimensional motion is given by \(v(t) = \) \(-5t^3 - 7t^2 - 4t\), where the units of \(v\) are in \(m/s\) and of \(t\) are in seconds,

Part 1#

The velocity and acceleration of the object at \(t = \) 18.3 \(s\) are:

Answer Section#

  • \(v = \) -33100.0 \(m/s\), \(a = \) -5280.0 \(m/s^2\)

  • \(v = \) -33100.0 \(m/s\), \(a = \) 0 \(m/s^2\)

  • \(v = \) -33100.0 \(m/s\), \(a = \) 9.81 \(m/s^2\)

  • \(v = \) 18.3 \(m/s\), \(a = \) -2640.0 \(m/s^2\)

  • \(v = \) -33100.0 \(m/s\), \(a = \) 5280.0 \(m/s^2\)

  • \(v = \) -33100.0 \(m/s\), \(a = \) -10600.0 \(m/s^2\)

Attribution#

Problem is licensed under the CC-BY-NC-SA 4.0 license.
The Creative Commons 4.0 license requiring attribution-BY, non-commercial-NC, and share-alike-SA license.