Velocity and Acceleration of an Object#
If the velocity of an object in one-dimensional motion is given by \(v(t) = \) \(-9t^2 - 5t\), where the units of \(v\) are in \(m/s\) and of \(t\) are in seconds,
Part 1#
The velocity and acceleration of the object at \(t = \) 12.1 \(s\) are:
Answer Section#
\(v = \) -1380.0 \(m/s\), \(a = \) -223.0 \(m/s^2\)
\(v = \) -1380.0 \(m/s\), \(a = \) 0 \(m/s^2\)
\(v = \) -1380.0 \(m/s\), \(a = \) 9.81 \(m/s^2\)
\(v = \) 12.1 \(m/s\), \(a = \) -112.0 \(m/s^2\)
\(v = \) -1380.0 \(m/s\), \(a = \) 223.0 \(m/s^2\)
\(v = \) -1380.0 \(m/s\), \(a = \) -446.0 \(m/s^2\)
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.