Shooting a Steel Ball#
A small steel ball is shot at 2 \(m/s\) at a 34\(^{\circ}\) angle above the horizontal direction and its motion is well approximated by projectile motion.
Part 1#
When the ball returns to its original height, its velocity \(\overrightarrow{v} = (v_x, v_y)\) is:
Answer Section#
\((2\cos(34^{\circ}), \; -2\sin(34^{\circ}))\)
\((2\cos(34^{\circ}), \;2\sin(34^{\circ}))\)
\((2\sin(34^{\circ}), \; -2\cos(34^{\circ}))\)
\((2\sin(34^{\circ}), \;2\cos(34^{\circ}))\)
\((-2\cos(34^{\circ}), \; -2\sin(34^{\circ}))\)
\((-2\sin(34^{\circ}), \;2\cos(34^{\circ}))\)
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.