Velocity and Acceleration of an Object#
If the velocity of an object in one-dimensional motion is given by \(v(t) = \) \(3t^2 + 5t\), where the units of \(v\) are in \(m/s\) and of \(t\) are in seconds,
Part 1#
The velocity and acceleration of the object at \(t = \) 13.3 \(s\) are:
Answer Section#
\(v = \) 597.0 \(m/s\), \(a = \) 84.8 \(m/s^2\)
\(v = \) 597.0 \(m/s\), \(a = \) 0 \(m/s^2\)
\(v = \) 597.0 \(m/s\), \(a = \) 9.81 \(m/s^2\)
\(v = \) 13.3 \(m/s\), \(a = \) 42.4 \(m/s^2\)
\(v = \) 597.0 \(m/s\), \(a = \) -84.8 \(m/s^2\)
\(v = \) 597.0 \(m/s\), \(a = \) 170.0 \(m/s^2\)
Attribution#
Problem is licensed under the CC-BY-NC-SA 4.0 license.